### Discussion :: Networking - Section 1 (Q.No.3)

Laxmi Kant said: (Sep 20, 2011) | |

Please explain the answer. |

M.Venkat said: (Nov 3, 2011) | |

1-1/1000 |

Suresh Kumar said: (Dec 9, 2011) | |

What is the method/theory to solve this question? |

Dipayan Das said: (Mar 3, 2012) | |

1bit error probability 1/1000 9bit error probability 9/1000 .ie .009 |

Aniruddha said: (Aug 13, 2012) | |

Here the data rate of 4800 bps is redundant information. Probability that a single bit is in error 10^-3 = 0.001t Probability that a single bit is not in error = 1 - 0.001 = 0.999 In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error. Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx) Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx) |

Sagar said: (Oct 30, 2012) | |

Thus, chances that all 9 bits are correct = 0.999*9 = 0.991 (approx) Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx) |

P.Tarun said: (Dec 20, 2012) | |

Here the data rate of 4800 bps is redundant information. Probability that a single bit is in error 10^-3 = 0.001t Probability that a single bit is not in error = 1 - 0.001 = 0.999 In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error. Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx) Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx) |

Geetu said: (Aug 9, 2015) | |

Please tell me how can I easily solve? |

Shivakumar_Bpt said: (Sep 8, 2016) | |

Probability that a single bit is in error 10^-3 = 0.001t. Probability that a single bit is not in error = 1 - 0.001 = 0.999. |

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